Find the surface area of a square pyramid with base edges of 8 feet. The height of each lateral face is 9 feet. Explain or
show how you got your answer.

MAKE THIS BRAINLIEST ANSWER IF THIS HELPED A LITTLE BIT!

A = L + B = a2 + a√(a2 + 4h2))

A = a(a + √(a2 + 4h2)) Is ya answer!

Slant Height of a square pyramid:

By the pythagorean theorem we know that

s2 = r2 + h2

since r = a/2

s2 = (1/4)a2 + h2, and

s = √(h2 + (1/4)a2)

This is also the height of a triangle side

Lateral Surface Area of a square pyramid (4 isosceles triangles):

For the isosceles triangle Area = (1/2)Base x Height. Our base is side length a and for this calculation our height for the triangle is slant height s. With 4 sides we need to multiply by 4.

L = 4 x (1/2)as = 2as = 2a√(h2 + (1/4)a2)

Squaring the 2 to get it back inside the radical,

L = a√(a2 + 4h2)

Base Surface Area of a square pyramid (square):

B = a2

Total Surface Area of a square pyramid:

A = L + B = a2 + a√(a2 + 4h2))

A = a(a + √(a2 + 4h2))

Square Pyramid Calculations:

the y will be in still but your answer will be y x 3

step-by-step explanation:

jk: )