8. Find the initial value: f'(x) = cos(2x), f(pi/4) = 0 *
O
f(x) = (1/2)sin(2x) + c
C = pi/4
O
O
f(x) = (1/2)sin(2x) + pi/4
O
O 0=-1/2
O
f(x) = (1/2)sin(2x) - 1/2

g(x) is the negative form of f(x)? because whenever its the negative form it reflects its self over the x axis. idk if this is right though.

step-by-step explanation:

#12 the answer is the third option

-8,5

step-by-step explanation:

the first sequence is an arithmetic sequence.