Michel uses the scale drawing and the scale factor to enlarge a square that has a side length of 12 in. A square with side lengths of 12 inches. Scale factor: 3 inches = 2 meters. Which proportion could Michel use to solve the side length, x, of the enlarged square? StartFraction 3 inches over 2 meters EndFraction = StartFraction x meters over 12 inches EndFraction StartFraction x inches over 2 meters EndFraction = StartFraction 3 inches over 12 meters EndFraction StartFraction 3 inches over x meters EndFraction = StartFraction 2 meters over 12 inches EndFraction StartFraction 3 inches over 2 meters EndFraction = StartFraction 12 inches over x meters EndFraction

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11-1 > 1-1+a

-12 > a

need more info

step-by-step explanation:

step-by-step explanation:

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