A spring attached to the ceiling is stretched 2.45 meters by a four kilogram mass. The mass is set into motion in a medium that imparts a damping force numerically equal to 16 times the velocity. If the mass is pulled down two centimeters and released, the solution for the position isa. x = 0.02e^2t - 0.04te^2t b. x =2e^-2t + 4te^-2t c. x = 0.02e^-2t + 0.04te^-2t d. x = e^-2t sint e. x = 0.02e^-2t cost

d. 9

step-by-step explanation:

54/12 = 4.5

sf = 4.5

so x = 2 · 4.5 = 9

send it over

step-by-step explanation:

answer: the angel abc is 30°,and the abc is a triangle where the angel bac is 90°

so ac is the half of 24=12ft,and from the pythagorean theorem we find ba

ba=√bc^2-ac^2=√576-144=√432=12√3ft

so bac is 12+12√3=12(1+√3)ft

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²