Identify the 42nd term of an arithmetic sequence where a1 = -12 and a27 = 66. (2 points)

70

72

111

114

111.

Step-by-step explanation:

The terms in an Arithmetic sequence are a1,  a1 + d,  a1 + 2d where a1 is the first term and  d is the common difference,

Therefore for this sequence the common difference is (a27 - a1) / 26

=  (66 - (-12) / 26

= 78/26

= 3.

The nth term an = a1 + (n - 1)d,  so

the 42nd term a42 = -12 + (42-1)*3

= -12 + 123

= 111.

the answer is d. 75%

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer