What’s the radius of a circle (x+2)^2 + (y-5)^2=9

Explanation:

The equation

(x+2)^2 + (y-5)^2=9

is the same as

(x-(-2))^2 + (y-5)^2=3^2

Compare this to

(x-h)^2 + (y-k)^2 = r^2

We see the center is (h,k) = (-2,5) and the radius is r = 3.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.