Two twins are running away from their mother in opposite directions one at a speed of 10 feet per second and the other at a speed of 8 feet per second. How much farther from each other will they be in one second?

if one run a speed of 10 feet per second and the other 8 feet per second I think it is 18 feet apart they will be because one run 10 feet and the other one run 8 so 10+8=18 feet apart from each other

v: l•w•h÷2.

v: 20•6•8 ÷2

v: 960÷2

v: 480

their is no graph showing

step-by-step explanation: