64^-x+52=128^x

Please help!

x = 23.999996

Step-by-step explanation:

Let's solve your equation step-by-step.

64−x+52=128x

Solve Exponent.

64−x+52=128x

log(64−x+52)=log(128x)(Take log of both sides)

(−x+52)*(log(64))=x*(log(128))

−x+52=(

log(128)

log(64)

)*(x)

−x+52=1.166667*x

−x+52=1.166667x(Simplify both sides of the equation)

−x+52−1.166667x=1.166667x−1.166667x(Subtract 1.166667x from both sides)

−2.166667x+52=0

−2.166667x+52−52=0−52(Subtract 52 from both sides)

−2.166667x=−52

−2.166667x

−2.166667

=

−52

−2.166667

(Divide both sides by -2.166667)

x=23.999996

Sorry is this is wrong, did it in a hurry :(

12*c

step-by-step explanation:

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true