“Using the matrix solver on your calculator, find the solution to the system of equations shown below.”
4x-y=3
6x-2y=2

O A. No solution
O B. x=2,y=5
O C. More than one solution
O D. x=5,y=2

x = 2 , y = 5

Step-by-step explanation:

Solve the following system:

{4 x - y = 3 | (equation 1)

6 x - 2 y = 2 | (equation 2)

Swap equation 1 with equation 2:

{6 x - 2 y = 2 | (equation 1)

4 x - y = 3 | (equation 2)

Subtract 2/3 × (equation 1) from equation 2:

{6 x - 2 y = 2 | (equation 1)

0 x+y/3 = 5/3 | (equation 2)

Divide equation 1 by 2:

{3 x - y = 1 | (equation 1)

0 x+y/3 = 5/3 | (equation 2)

Multiply equation 2 by 3:

{3 x - y = 1 | (equation 1)

0 x+y = 5 | (equation 2)

Add equation 2 to equation 1:

{3 x+0 y = 6 | (equation 1)

0 x+y = 5 | (equation 2)

Divide equation 1 by 3:

{x+0 y = 2 | (equation 1)

0 x+y = 5 | (equation 2)

Collect results:

{x = 2 , y = 5

i do not know the answer i am sorry

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!