Over which interval does a valid solution exist for dy/dx=−2/(x^(3))+2e^(2x−2)?

D

Step-by-step explanation:

-2×(x^-3) + 2e^(2x-2) = dy/dx

Integrate for y

y = -2×(x^-2)÷-2 + 2[e^(2x-2) ÷ 2] + c

y = 1/x² + e^(2x-2) + c

y is undefined only at x² = 0

Because x² is in the denominator

b

step-by-step explanation:

given

- 2 (3x + 12y - 5 - 17x - 16y + 4 )

simplify the parenthesis by collecting like terms

= - 2 (- 14x - 4y - 1) ← distribute the parenthesis by - 2

= 28x + 8y + 2 → b

your answer is the frist one

hop i