Jean bought a bag of candy that contained red candies, green candies, and brown candies. some candies are marked with a smile and others are not marked. the probabilities are displayed in the table below:

| red |green |brown
smile |0.100 | .300 | .10
no smile |0.200 | .150 | .15

if a random candy is chosen from this bag, what is the probability that the candy was red or had no smile?

                   | Red    |Green  | Brown   Total
Smile         |0.100  | .300    | .10           0.50
No smile   |0.200  | .150    | .15            0.50
Total           0.30       0.45      0.25         1.00

The probability of choosing red candy is 0.10
The probability of choosing no smile candy is 0.50

The probability of choosing red or no smile = 0.10 + 0.50 = 0.60

I did not use 0.30 as the probability of red because it included the no smile candy. It should only be red candy that has a smile.

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The answer would be a