Find the x-intercepts and the coordinates of the vertex for the parabola Y equals negative X squared plus 8X -12. If there’s more than one X intercept, separate them commas.

x = 2, and 6

x = 2 , 6

Step-by-step explanation:

The quadratic function to analyze is:

In order to find where the corresponding parabola intercepts the x axis, we set it equal to zero (y = 0):

This equation is easy to solve by factoring. We look for a air of integer numbers whose product equals the constant term "12", and whose combinig renders the coefficient of the middle term of the trinomial "-8".

The two such numbers are "-2" and "-6". We use them to split the middle term, and then solve by factoring by grouping:

For the product of two factors to render zero, we need either one to be a zero.This means that (x-2)=0 (that is x = 2), or (x-6)=0 (that is x = 6).

So, there are two x-intercepts: x= 2, and 6

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation: