Plz help derive ln(sinx)

cot(x)

Step-by-step explanation:

ln(sin(x)) = =

Step-by-step explanation:

I'm assuming you want to find the derivative of the function y = ln (sin x).

If this is the case, let's look at the derivatives of y = ln x and y = sin x separately and then use the results as appropriate:

(d/dx) ln x = 1/x

(d/dx) ln u = (1/u)(du/dx)

(d/dx) sin x = cos x

We'll also need to use the Chain Rule (which we have done in finding the derivative of ln u, above).

                                  1                                       1                        cos x

(d/dx) ln (sin x) = * (d/dx) (sin x) = * cos x = = cot x

                               sin x                                 sin x                      sin x

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation: