Mathematics, 08.04.2020 20:21 BardiFan
If A is invertible and similar to B, then B is invertible and A−1 eh super negative 1 end super is similar to B−1. b super negative 1 end super , . [Hint: P−1AP=B p super negative 1 end super eh p equals b for some invertible P. Explain why B is invertible. Then find an invertible Q such that Q−1A−1Q=B−1. q super negative 1 end super . eh super negative 1 end super q equals , b super negative 1 end super , .
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If A is invertible and similar to B, then B is invertible and A−1 eh super negative 1 end super is s...
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