How to use a square to visualize Pythagorean theorem?

Possible Answers:
8, 58
7, 60
11, 56

Given:

Area of the largest square = 67 units²

To find:

The area of the smallest squares.

Solution:

Area of square = s²

s² = 67

Here hypotenuse of the right triangle = Side of the largest square

Using Pythagoras theorem,

In right triangle, square of the hypotenuse is equal to the sum of the squares of the other two sides.

Checking possible answers:

Option A: 8 and 58

Using Pythagoras theorem,

8 + 58 = 66

This is not equal to 67.

It is not true.

Option B: 7 and 60.

Using Pythagoras theorem,

7 + 60 = 67

This is equal to 67 (hypotenuse)

It is true.

Option C: 11 and 56

Using Pythagoras theorem,

11 + 56 = 67

This is equal to 67 (hypotenuse)

It is true.

Therefore 7, 60 and 11, 56 could be the areas of the smaller squares.

step-by-step explanation:

i think its about 8