In ΔABC, the measure of ∠C=90°, the measure of ∠A=49°, and BC = 5.1 feet. Find the length of AB to the nearest tenth of a foot.

Given:

In ΔABC, the measure of ∠C=90°, the measure of ∠A=49°, and BC = 5.1 feet.

We need to determine the length of AB

Length of AB:

The image of the triangle ABC is attached below.

Using the figure, we shall determine the length of AB by the trigonometric ratio.

Thus, we have;

where , and

Thus, we have;

Substituting BC = 5.1, we get;

Simplifying, we have;

Dividing, we get;

Rounding off to the nearest tenth, we get;

Thus, the length of AB is 7.8 feet.

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

u dumb boi

step-by-step explanation: