You might need: Calculator Problem Suppose that Antonia rolls a pair of fair six-sided dice. Let AAA be the event that the first die lands on 555 and BBB be the event that the sum of the two dice is 666. Using the sample space of possible outcomes below, answer each of the following questions. What is P(A)P(A)P, (, A, ), the probability that the first die lands on 555

P(A)=1/6

Step-by-step explanation:

The sample space of the two dice is given below:

[1, 1], [1, 2], [1, 3], [1, 4], [1, 5], [1, 6]

[2, 1], [2, 2], [2, 3], [2, 4], [2, 5], [2, 6]

[3, 1], [3, 2], [3, 3], [3, 4], [3, 5], [3, 6]

[4, 1], [4, 2], [4, 3], [4, 4], [4, 5], [4, 6]

[5, 1], [5, 2], [5, 3], [5, 4], [5, 5], [5, 6]

[6, 1], [6, 2], [6, 3], [6, 4], [6, 5], [6, 6]

n(S)=36

Let A be the event that the first die lands on 5

Sample Space of Event A is:

[5, 1], [5, 2], [5, 3], [5, 4], [5, 5], [5, 6]

n(A)=6

Therefore:

P(A)=n(A)/n(S)

=6/36

=1/6

she played for 18.75 hours.

step-by-step explanation:

if she played 2/4 of a hour on tuesday. and there is 60 minutes in an hour and 60 divided by 4 is 7.5. and she played 2/4 of an hour on thursday then again 60 divided by 4 is 7.5, you add 7.5+7.5=56.25. now you have to do 1/4 of an hour, it equals 3.75. now you have to add them all up. 3.75+7.5+7.5=18.75

i hope this and i hope you get it right. it took me a while to get this done for you. : )

add an !

step-by-step explanation: