When graphed, y = -x + 3 and y = x - 7 produce the graph
seen at the right. From looking at the graph, the solution
to this system of equations is:
a. (3,0)
b. (7,0)
c. (0,3)
d. (5,-2)
e. (0,-7)

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

what do you mean

have a great day

feed your rabbit lettuce.

a: kite

step-by-step explanation:

figure lmno is located at l (1, 2) m (3, 2), n (3, 0), and o (0, −1). use coordinate geometry to best classify quadrilateral lmno.