Question 7 (10 points) Given f(x)=(x−2)2(x−4)2 , determine a. interval where f(x) is increasing or decreasing, b. local minima and maxima of f(x) c. intervals where f(x) is concave up and concave down, and d. the inflection points of f(x) . Sketch the curve, and then use a calculator to compare your answer. If you cannot determine the exact answer analytically, use a calculato

b. x=2,3,4

c.

x=2 is a local minimum

x=3 is a local maximum

x=4 is a local minimum

d.

Step-by-step explanation:

a. You have the function

to find the intervals you have to take into account the roots of f(x), in this case you have the roots

- for x < 2, for example x=1:

f(x) decreases from infinity to zero

- for 2 < x < 4, for example x=3:

between x=2 and x=3 f(x) increases. But between x=3 and x=4 f(x) decreases because f(4)=0.

- for x > 4:

f(5)>0

f(x) increases for x > 4.

b. You have to compute the derivative to find local minima and maxima

and by taking f'(x)=0:

Local minima and maxima are found by evaluating the roots of f'(x) in the second derivative f''(x)

Hence

x=2 is a local minimum

x=3 is a local maximum

x=4 is a local minimum

c.

to find the concavity you have to find the inflection points

Hence:

for -infinity < x < x1 --> concave up

for x1 < x < x2 --> concave down

for x2 < x < infinity --> concave up

d.

based on context clues you gave i'm assuming the answer would be c.

ruth is 6 years old

step-by-step explanation:

6 + 24 = 30,   so 6/30 = .2  

if you do 1/5 it also equals .2, so that is the answer.