The average number of customers arriving at an ATM machine is 27 per hour during lunch hours. Use equation to denote the number of arrivals in a 5 minute time interval. Assume the customers arrive independently and the number of arrivals within each 5 minutes follows a Poisson distribution. Keep at least 4 decimal digits if the result has more decimal digits. The probability that exactly 2 customers arrive in a given 5 minute interval is closest to

The probability that exactly 2 customers arrive in a given 5 minute interval =  0.2667

Step-by-step explanation:

Given -

The average number of customers arriving at an ATM machine is 27 per hour during lunch hours. then the average number of customers arriving at an ATM machine n a 5 minute time interval = = 2.25

average number of customers arriving at an ATM machine n a 5 minute time interval = 2.25

Let X denote the no of customer arrivals in a 5 minute time interval

The probability that exactly 2 customers arrive in a given 5 minute interval =

P( X = 2 )  =            ( Using poision distribution )

               =  

               =

               =   0.2667

a

step-by-step explanation:

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2