A population of muskrats oscillates 33 above and below average during the year, hitting the lowest value in january. the average population starts at 900 muskrats and increases by 7 % each month. find an equation for the population p in terms of the months since january t

P = 867(1.07)^t

Step-by-step explanation:

The population of muskrats oscillates 33 above and below average during the year, hitting the lowest value in january.

If the average value = 900 muskrats

Then the lowest = 900 - 33 = 867

It increases by 7 % each month

R = 7%

equation for the population p in terms of the months since january t will be

P = Po( 1 + R%)^t

P = 867( 1 + 0.07) ^t

P = 867(1.07)^t

jml angle lkj & angle mj = lm

i think the answer is b