A bicycle lock requires a two-digit code of numbers 1 through 9, and any digit may be used only once. Which expression would determine the probability that both digits are even?

P(both even) = StartFraction (4 P 1) (3 P 1) Over 9 P 2 EndFraction
P(both even) = StartFraction (4 C 1) (3 C 1) Over 9 C 2 EndFraction
P(both even) = StartFraction (5 P 1) (4 P 1) Over 9 P 2 EndFraction
P(both even) = StartFraction (5 C 1) (4 C 1) Over 9 C 2 EndFraction

The answer is the first one.

P(both even) = (4P1)(3P1) / 9P2

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.

according to egenuity the answer is

step-by-step explanation:

d. 344.22