The U. S. Department of Education reported that in 2007, 67% of students enrolled in college or a trade school within 12 months of graduating from high school, in 2013, a random sample of 160 individuals who graduated from high school 12 months prior was selected. From this sample, 102 students were found to be enrolled in college or a trade school. A.) construct a 90% confidence interval to estimate the actual proportion of students enrolled in college or a trade school within 12 months of graduating from high school in 2013. B.) What is the margin of error for this sample

a) The 90% confidence interval is

b) The margin of error is 0.063.

Step-by-step explanation:

We have to construct a 90% confidence interval for the proportion of students enrolled in college or a trade school within 12 months of graduating from high school in 2013.

We have a sample of 160 students, and a proportion of:

The standard deviation is:

As the sample size is big enough, we use the z-value as statistic. For a 90% CI, the z-value is z=1.645.

Then, the margin of error is:

Then, the 90% confidence interval is:

0 is its x and y coordinate

#15. square

step-by-step explanation:

because quadrilatural (idk how to spell it) means somthing that is not 3d or like, equal sides (or somthing like that   you know what i meanz)

hope this halps!

bai!