Let X be a binomial random variable with n = 9 and p = 0.2 (nine trials, probability of success = 0.2). Find the probability of 4 successes, i. e., P(X = 4). Give your answer as a decimal to three decimal places, e. g., 0.123. Round as needed.

The probability of 4 successes,

P(X=4) =0.0660

Step-by-step explanation:

Step 1:-

Let X be a binomial random variable with n = 9 and p = 0.2

probability of successes p = 0.2

probability of failure q = 1-p = 1-0.2 = 0.8

By using binomial distribution

Step 2:-

The probability of 4 successes, i.e.,

by using

P(X=4) =0.0660

conclusion:-

The probability of 4 successes, that is P(X=4) =0.0660

if y=4x then you will substitute 4x in for y in the second equation.

8x + 4x = 18 combine like terms

12x = 18 divide by 12 on both sides

x = 18/12 or 3/2

now replace x in the first equation with 3/2 to get

y = 4 3/2

y = 6

the answer is a

(3/2,6)

hope that .

brainliest is always apprectiated