Surveys indicate that 5% of the students who took the SATs had enrolled in an SAT prep course. 30% of the SAT prep students were admitted to their first choice college, as were 20% of the other students. You overhear a classmate say he got into the college he wanted. What is the probability he didn't take an SAT prep course?

What steps would I take to solve this problem?

The probability he didn't take an SAT prep course = 0.985

Step-by-step explanation:

Let us first assume that he took SAT prep.

Surveys indicate that 5% of the students who took the SATs had enrolled in an SAT prep course. 30% of the SAT prep students were admitted to their first choice college. That is,

30/ 100 of 5 = 0.3 × 5 = 1.5

The probability he did take an SAT prep course and got admission into the college of first choice will be

P(prep) = 1.5 / 100 = 0.015

The probability he didn't take an SAT prep course will be:

P(not prep) = 1 - P(prep)

P(not prep) = 1 - 0.015

P(not prep) = 0.985

the equation for this situation is y=122+45. to solve the equation you would add 45 and 122 to get a total of 167lbs. in conclusion, grace's weight eight weeks ago was 167lbs.  

c

step-by-step explanation: