Suppose the population proportion of American citizens who are in favor of gun control is .61. If a sampling distribution of size n= 50 was created from this population, what would be the mean of this sampling distribution?

The Mean of the sampling distribution is μ = p = 0.61

Step-by-step explanation:

Given size of the sampling distribution (n) = 50

Suppose the population proportion of American citizens who are in favor of gun control is .61

That is p = 0.61

Sampling distribution of proportions:-

Let p be the probability of occurrence of an event (called its success) and q =1-p is the probability of non- occurrence (called its failure).Draw all possible samples of size n from an infinite population.

Compute the proportion P of success for each of these samples. Then

and variance sampling distributions are given by

      and

variance  

Standard deviation (S.D) =

Mean of the sampling distribution:-

The Mean of the sampling distribution is μ = p

Given data the proportion of American citizens who are in favor of gun control is 0.61

p = 0.61

The Mean of the sampling distribution is μ = p = 0.61

1/5^2 = 7.56/45

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1