ABC has vertically casts a 19-foot shadow. At the same time, a 6-foot person near the be cast a shadow 4 feet 9 inches. What is the height of the beam

24 ft

Step-by-step explanation:

The first step is to have uniform units hence we convert the inches to ft.

Conversion

1 inch is equal to 0.0833 ft hence 9 inches will be 9*0.0833=0.75 ft

The shadow of the man is 4.75 ft while actual height is 6ft

By cross multiplication concept, we evaluate that

6ft=4.75 ft shdow

X ft= 19 ft shadow

X=6*19/4.75=24 ft

Therefore, the actual beam height is 24 ft

the answer is c.

for continuous functions, they continue in the same pattern and you have to find that pattern kinda like slope

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐