Mathematics, 08.04.2020 00:12 jesussaves333

(1 point) A student was asked to find the equation of the tangent plane to the surface z=x2−y3 at the point (x, y)=(5,1). The student's answer was z=24+2x(x−5)−(3y2)(y−1). (a) At a glance, how do you know this is wrong. What mistakes did the student make? Select all that apply.

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Answer from: khanhlan7213

Options a and d are the correct ones.

Step-by-step explanation:

The complete question is as follows

A student was asked to find the equation of the tangent plane to the surface z = x^2-y^3 at the point (x,y)=(5,1). The student's answer was z = 24+2x(x-5)-3y^2(y-1) . (a) At a glance, how do you know this is wrong. What mistakes did the student make? Select all that apply.

a) The answer is not a linear function

b) The (x-5) and (y-1) should be x and y

c) the 24 should not be in the answer

d) the partial derivatives were not evaluated at the point

e) all of the above.

Recall that, given a surface of the form z=f(x,y) where f is differentiable, then at a given point (x_0,y_0) we can find the equation of the tangent plane by

$z=f(x_0,y_0)+\frac{df}{dx}(x_0,y_0) (x-x_0)+\frac{df}{dy}(x_0,y_0) (y-y_0)$

We are given that (x_0,y_0) = (5,1) Note that f(5,1) = 24. Then, c is not true. Also, the formula says that we must have the factors (x-5) and (y-1), since we are evaluating the tangent plane in a neighborhood of that point, hence option b is not true. Since B and C are not true, then E is not true. Note that the given function by the student has a mutiplication of 2x and (x-5) which will give us the function 2x^2-10 which is of degree two. Then, the function given by the student is not a linear function, since linear functions have a degree at most 1. Finally, we must check that d is also true.

REcall that

$\frac{df}{dx} = 2x, \frac{df}{dy} = -3y^2$

so we see that this coincide with the the terms that multiply the factors (x-5) and (y-1) respectively, which tell us that even though the student was trying to follow the formula, he/she forgot to evaluate the partial derivatives at the given point, hence the option D is also true.

Recall that if we want the tangent plane at the point given, we must evaluate the partial derivatives at x=5 and y=1. Hence, the formula of the tangent plane is

z = 24+10(x-5)-3(y-1)

Answer from: Quest

for the first question it would be the second answer for the second question it would be the third answer and for the third question it would be the first answer

step-by-step explanation:

Answer from: Quest

Most of them do but everyone doesn’t get exactly the same questions on every quiz so there will also be questions you’ve never had. you can find a lot online though like on quizlet and on here.

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(1 point) A student was asked to find the equation of the tangent plane to the surface z=x2−y3 at th...

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