Two cars leave an intersection at the same time. One heads due south at 55 mph. The other travels due west. After 2 hours, the bearing of the car headed west from the car headed south is 324 . How far apart are they at that time?

136 miles

Step-by-step explanation:

Distance is product of speed and time.

Given the car that moves South takes 2 hours then the speed is 55 mph

D=st

Where s is speed, t is time and D is distance covered. Substituting 2 hours for time and 55 mph for s then

Distance=2*55=110 miles

Using trigonometry

Cos 36°=110/x

X=110/cos 36°=135.967477524977 miles

Alternatively

X=110/sin 54°=135.967477524977

Rounded off, this is approximately 136 miles

step-by-step explanation:

this is not a question

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p