Find dy/dx implicit differentiation of each equation and evaluate at the given point to find the slope at that point.

(x+y)3=x3+y3 at (-1,1)

Differentiate both sides with respect to . By the power and chain rules, we have

Solve for :

At the point (-1, 1), the slope of the tangent line to the curve is

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

dont trust me im no expert these losers made me fail a test bro this sucks

step-by-step explanation: