A rectangular field is to be enclosed on four sides with a fence. fencing costs 5$ per foot two opposite sides, and 6$ per foot for the other two sides. find the dimensions of the feild of area 710ft

Length of cheaper side = x = 29.21 ft

Length of expensive side = y = 24.31 ft

Step-by-step explanation:

Let

Length of cheaper side = x

Length of expensive side = y

Total Cost = 5(x + x) + 6(y+y) =

Total Cost = 5(2x) + 6(2y)

Total Cost  = 10x + 12y

we also know that

xy = 710ft square

so

y = 710 ft sq. / x

Putting this in total cost equation

Total Cost  = 10x + 12( 710 ft sq. / x )

f(x)  = 10x + ( 8,520 ft sq. / x )                 ( cost = f(x)

f'(x)  = 10 - ( 8,520 ft / x^2 )                 (x>0)

0 + ( 8,520 ft / x^2 ) = 10

8,520 ft / x^2 = 10

x^2 = 8,520 ft / 10

(x^2)^1/2 = (8,520 ft / 10)^1/2

x = 92.3 / 3.16

x = 29.21 ft

As given

xy = 710ft square

Putting value of x in above equation

29.21 y = 710

y = 710/29.21

y = 24.31 ft

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

pretty sure 750 each month!

step-by-step explanation: