Determine all critical points for the following function. f (x )equals 2 x (4 minus x )cubedf(x)=2x(4−x)3 xequals=nothing (Use a comma to separate answers as needed.)

The critical points of the function

f(x) = 2x(4 - x)³

are x = (1, 4)

Step-by-step explanation:

Given the function

f(x) = 2x(4 - x)³

To find the critical points, we differentiate f(x) to obtain f'(x), and then find the zeros of the resulting quadratic function.

Now, differentiate f(x).

f'(x) = 2(4 - x)³ + 2x(-1)×3(4 - x)²

= 2(4 - x)³ - 6x(4 - x)²

= 2(4 - x)²(4 - x- 3x)

= 2(4 - x)²(4 - 4x)

f'(x) = 8(4 - x)²(1 - x)

Now we set f'(x) = 0 and solve

8(4 - x)²(1 - x) = 0

=> 8(1 - x) = 0

=> 1 - x = 0

=> x = 1

Or

(4 - x)² = 0

x = 4 twice.

So x = (1, 4)

Therefore, the critical points are x = (1, 4)

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.