A 2x6 exterior stud wall is 14-ft tall. Studs are 16-in. o. c. The studs support the following vertical loads per foot of wall: D= 800 lb/ft, L=800 lb/ft, Lr=400 lb/ft. In addition, the wall carries a uniform wind force of 15 psf (horizontal). Lumber is No. 1 DF-L. Cm=1.0, Ct=1.0, and Ci=1.0. Sheathing provides lateral support in the weak direction. Find: a. Check the studs using ASD and the IBC-required load combinations. Neglect uplift.

answer: none of these answers are correct only the second half is

step-by-step explanation:

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6: 4= 3/2

18: 8= 9/4

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let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.

measurement of the swimming pool is given as = 7 yards 4.79 feet

first we will convert this to yards only.

1 foot = 0.33 yards

so, 4.79 feet = yards

so total yards are = yards

now we will convert this in meters.

1 yard = 0.914 meters

8.580 yards = meters

0.842 m = 0.842*100 = 84.2 cm

this becomes 7 meters and 84.2 cm

hence, the pool is 7 meters and 84.2 cm wide.