H(t)=(t+3)
2
+5h, left parenthesis, t, right parenthesis, equals, left parenthesis, t, plus, 3, right parenthesis, squared, plus, 5
What is the average rate of change of hhh over the interval -5\leq t\leq -1−5≤t≤−1minus, 5, is less than or equal to, t, is less than or equal to, minus, 1?

0

Step-by-step explanation:

h(t) = (t + 3)² + 5, -5 ≤ t ≤ -1

The average rate of change is the change in h over the change in t.

(h(-1) − h(-5)) / (-1 − (-5))

= ((-1 + 3)² + 5 − ((-5 + 3)² + 5)) / (-1 + 5)

= (4 + 5 − 4 − 5)) / 4

= 0

lol we need to see what the question is asking about

step-by-step explanation:

c

step-by-step explanation: