A mountain has a snow line at an elevation of about 9,000 feet which runs parallel to its base. From your patio, the mountain looks like a triangle. The length of the snow line is 2.4 times the height of the snow covered part of the mountain. a. If the snow covers about 1,200,000 square feet of the part of the mountain you can see, how high is the mountain? b. What percentage of the part of the mountain that you can see is covered in snow?

a. The height of the mountain = 1000 ft + 9000 ft = 10000 ft

b. Percentage  covered with snow = 1%

Step-by-step explanation:

The diagram below illustrate how the snow line formed on the triangular mountain as described.

Area of a triangle = 1/2  × base × height

The upper section of the triangle where the snow line cut, the height h can be calculated below

Area of a triangle = 1/2  × base × height

Area of a triangle = 1/2 × 2.4 h × h

1200000 = 2.4h²/2

cross multiply

1200000 × 2 = 2.4h²

2400000  = 2.4h²

divide both sides by 2.4

h² = 2400000/2.4

h² = 1000000

h = √1000000

h = 1000  ft

The height of the mountain = 1000 ft + 9000 ft = 10000 ft

b.  the snow line is parallel with base of the mountain

snow line base  = 2.4 × 1000 = 2400

base of the mountain = 2.4 × 10000 = 24000

area of the mountain = 1/2 × 24000 × 10000

area of mountain = 240000000/2

area of mountain = 120000000  ft²

Percentage  covered with snow = 1200000/120000000  × 100

Percentage  covered with snow = 120000000/120000000

Percentage  covered with snow = 1%

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v