A company has 125 personal computers. The probability that any one of them will require repair on a given day is 0.15.

Which of the following is one of the properties required so that the binomial distribution can be used to compute the probability that no more than 2 computers will require repair on a given day?

a. the probability that any one of the computers will require repair on a given day is constant

b. The probability that a computer that will require repair in the morning is the same as the in the afternoon.

c. The # of computers that will require repair in the morning is independent of the # of computers that will require repair in the afternoon.

d. The probability that 2 or more computers that will require repair in a given day approaches zero

a. the probability that any one of the computers will require repair on a given day is constant

Step-by-step explanation:

The following properties must be true in order for a distribution to be binomial:

- A fixed number of trials (125 computers)

- Each trial is independent of the others (one computer requiring repair does not interfere with the likelihood of another requiring repair).

There are only two outcomes (requires repair or do not require repair)

The probability of each outcome remains constant from trial to trial (All computers have the same likelihood of requiring repair, 0.15).

Therefore, the alternative that better fits those properties is alternative a. the probability that any one of the computers will require repair on a given day is constant

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a