Suppose that a bored student wants to go to a restaurant for lunch, but she only has an hour in which to go, eat, and get back in time for class. Considering that it usually takes about 30 minutes in most restaurants to get served and to eat, what is the farthest restaurant the student can go to without being late for class

Missing information

Take local speed ad 30 mph and express your answer in miles

7.5 miles

Step-by-step explanation:

Time for lunch is 1 hour but once will wait for 30 minutes before served and eat.

Out of 1 hour, 30 mins is for service and eating to mean time to get from work to restaurant, to and fro is the other 30 mins

Since 30 mins is for to and fro, then one way direction takes 15 mins.

Speed, s=d/t and distance d=speed*time

Given local speed of 30 mph and time as 15 mins,

To convert minutes to hours, we divide it by 60 hence the distance is

30*15/60=7.5 miles

Therefore, the student can go to a restaurant that is 7.5 miles from the office.

step-by-step explanation:

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is           symmetric about the line y = 120,000.

step-by-step explanation:

given that megan owns a clothing boutique.

the profits of 2010, 11, are recorded and shown as follows:

years since     2010 0     1     2     3       4       5

profits made in 1000's   39       84     111     120   111     84

we find that profit gradually increases form 2010 to 2013 upto 120,   then starts decreasing.

the profits for 2012 and 2014 are the same while that of 2011 and 2015 are also the same.

this shows that there is symmetry about the line profit = 120000

hence answer is:

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is           symmetric about the line y = 120,000.

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