A beef rancher randomly selected 42 cattle from her large herd to obtain a 95% confidence interval to estimate the mean weight of the cows in the herd. The interval obtained was (1010, 1321). If the rancher had used a 98% confidence interval instead, the interval would have been .

Wider and less accurate than the original estimate

Step-by-step explanation:

We now use a 98% confidence interval instead of a 95% confidence interval, which means that the confidence level increases. As the confidence level increases, the confidence that the confidence interval contains the real mean increases, which means that the confidence interval must contain more possible values for the mean, which implies that the confidence interval is more wider and being broader is less accurate

Therefore, the interval would have been wider and less accurate than the original estimate.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

d. 8

step-by-step explanation:

the given radical expression is:

we can rewrite this as:

we express as square numbers to get;

the exponents will now cancel out to give.

the correct answer is d