0.2x + 0.3y = 1.3.
0.4r + 0.5y = 2.3. solve by using substitution

x=2, y=3.

Step-by-step explanation:

0.2x + 0.3y = 1.3

0.4x + 0.5y = 2.3

From the first equation   y = (1.3 - 0.2x) / 0.3

Substituting in second equation:

0.4x + 0.5(1.3 - 0.2x) / 0.3 = 2.3

Multiply through by 0.3:

0.12x + 0.5(1.3 - 0.2x) =  0.69

0.12x + 0.65 - 0.1x = 0.69

0.02x = 0.04

x = 2.

Substituting for x in equation 1:

0.2* 2 + 0.3y = 1.3

0.4 + 0.3y = 1.3

0.3y = 1.3 - 0.4 = 0.9

y = 3.

Check in equation 2:

0.4 * 2 + 0.5(3) =   0.8 + 1.5 = 2.3.

- Correct.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

c. 6tan80

step-by-step explanation: