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Mathematics, 21.06.2019 14:30
Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tauâŤ0tv(Ď) dĎ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equalsâ¤tless than or equalsâ¤startfraction pi over 3 endfraction Ď 3.
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Mathematics, 21.06.2019 15:30
Come up with a new linear function that has a slope that falls in the range 10 m â < < . choose two different initial values. for this new linear function, what happens to the functionâs values after many iterations? are the functionâs values getting close to a particular number in each case?
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Mathematics, 21.06.2019 22:30
5. (04.07)which of the following exponential functions goes through the points (1, 12) and (2, 36)? (2 points)f(x) = 3(4)^xf(x) = 4(3)^-xf(x) = 3(4)^-xf(x) = 4(3)^x
Answers: 1
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