Solve.3. The low temperature was 35°F. This was 13°F lower than the daytimehigh temperature. Write an equation to determine whether the hightemperature was 48°F or 42°F.

  h -13° = 35°

Step-by-step explanation:

Let h represent the high temperature. Then h-13° is the low temperature, which is 35°. So, an equation that can be used is ...

  h -13° = 35°

Adding 13° to both sides of the equation tells us the high temperature was 48°.

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068