Can someone help me with my math?!?!?!?! ASAP

horizontal = 0 slope

vertical = undefined

1. y = -3

The line has 0 slope, but its y-intercept is -3.

2. y = 2, 0 slope, (4,6) (5,6) (6,6) (7,6)

A horizontal line has 0 slope, but has a y-intercept, and the y-value does not change in a horizontal line.

3. x = 7

The vertical line has an undefined slope, since it is only going up. But because the line must go through the point given, it needs to be 7 units from the origin.

4. True

Horizontal lines have 0 slope, but do have a y-intercept and a constant y-value.

5. It is vertical

m = (4 - - 1) / (7 - 7)

m = 5 / 0 = undefined

The slope is undefined and the x value is constant through both points.

6. y = 3

The line has a y-intercept of 3 and 0 slope.

7. y = 3

The x-value does not matter for the equation of a horizontal line, only the y-value. We want it to go through the 3rd value above the origin, so our equation should be as shown.

8. The third option

x = -2 is a vertical line, of which goes through the point (-2, 0).

9. y = -1

The y-value is constant in both points, so this line should be horizontal and go through the y-value that is the same in both points.

10. x = 2

Any vertical line begins with x = ? and can have any number after the equal sign. An example is given.

Hope this helps!! :)

45

step-by-step explanation:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)