In right triangle QRS, Angle S is a right angle, QS = 33, SR = 56, and QR = 65. What is
the value of the sine of Angle Q?

The value of sine of angle Q is 1.16

Explanation:

Given:

ΔQRS is a right angle triangle

∠S = 90°

QS = 33

SR = 56

QR = 65

Sin(∠Q) = ?

We know:

So,

Therefore, the value of sine of angle Q is 1.16

ok so the answer to your question is simple as long as you look at the different dimensions that contain the exemplary letters that combined in the right order give you words that eventually within the 5th dimension will conform and give you the correct answer to your question. hope i , stop looking at this easily, look at it with a spectral view.

step-by-step explanation:

told you

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v