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Mathematics, 06.04.2020 21:45 gugu1004
\begin{cases}b(1)=16 b(n)=b(n-1)+1 \end{cases}
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b(1)=16
b(n)=b(n−1)+1
Find the 2^{\text{nd}}2
nd
2, start superscript, start text, n, d, end text, end superscript term in the sequence.
Answers: 2
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\begin{cases}b(1)=16 b(n)=b(n-1)+1 \end{cases}
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