Circle C with tangents AB and AD is shown. BC=7, and EA=18.

What is the length of one of the tangent segments, to the nearest tenth?

A.
16.6
B.
19.3
C.
24.0
D.
26.0

The answer is C.

Step-by-step explanation:

In Circle Theorem, it is given that tangent is 90° to the radius of circle. We can use Pythogaros' Theorem as it can only be used in a right-angle triangle. The formula of Pythogaros' Theorem is hypo² = side² + side² :

AC = CE + EA

= 7 + 18

= 25 units

hypo = AC

= 25 units

side = CD & AD or BC & AB

The question wants us to find the length of one of the tangent segment which is either AB or AD as both of them are tangent to the circle so they will also give the same answer :

Let's find AB,

AB² = AC² - BC²

= 25² - 7²

= 625- 49

= 576

AB = √576

= 24 units

Let's find AD,

AD² = AC² - CD²

= 25² - 7²

= 576

AD = √576

= 24 units

b. x- 48 =120

step-by-step explanation:

the answer is c: divide the arc's degree measure by 360°, then multiply by the circumference of the circle.