Find the volume of a right circular cone that has a height of 9.1 cm and a base with a circumference of 13.3 cm. Round your answer to the nearest tenth of a cubic
centimeter.

Volume = 42.8 cubic centimeters

Step-by-step explanation:

The volume of right circular cone is:

Where

r is the radius

h is the height

We are given height of 9.1 cm

h = 9.1

We aren't given radius explicitly, we are given circumference of 13.3, so we need to figure out radius from that. Lets do this:

So,

r = 2.12

Now, substituting in cone formula, we get the volume to be:

Rounded to nearest 10th is 1 decimal place, so

Volume = 42.8 cubic centimeters

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)