Farmer Samantha has a cylindrical grain silo with a diameter of 12 feet and a height of 40 feet. The silo is filled with grain that weighs approximately 48 pounds per cubic foot. Samantha knows that each of the cows on her farm will eat approximately 28 pounds of grain per day. If the grain silo is full, approximately how many pounds of grain will remain after the 20 cows eat for 100 days? Round your answer to the nearest pound.

161,234 pounds of grain will remain in the silo

Step-by-step explanation:

In this question, we are to calculate the amount of grains that will be left in a silo if 20 cows feed on the content for 100 days.

Firstly, we need to calculate the amount of grains present in the silo.

This we can do by first calculating the volume of the silo. Since it is cylindrical in shape, we apply the formula for the volume of a cylinder.

Mathematically, the volume of a cylinder is

V = pi * r^2 * h

Here we have the r = D/2 = 12/2 = 6 feet and h = 40 feet. Plugging this , we have;

V = pi * 6^2 * 40 = 1440pi cubic feet

Now, per cubic feet, we have a weight of 48 pounds. The weight of grains thus present in the silo is thus;

1440pi * 28 = 1440 * pi * 48= 69,120pi pounds of grain

Let’s calculate what the cows would feast on. That would be 20 * 28 * 100 = 56,000 pounds of grains

Now we need to know what will remain. We just need to subtract what is consumed by the cows from we have inside the silo

What is inside the silo would be 69,120 * 22/7 = apprx 217,234 pounds

What will remain is thus 217,234 - 56,000 = 161,234 pounds of grain

eve and marks ratios are equivalent

step-by-step explanation:

26 is 33.33% of 78

step-by-step explanation:

26 is what percent of 78?

26 is p% of 78

equation: y = p% * x

solving our equation for p

p% = y/x

p% = 26/78

p = 0.3333

convert decimal to percent:

p% = 0.3333 * 100 = 33.33%