Please I really need help! I will mark you as brainliest if the answer is correct!

Given:

PQRS is a rectangle and XY is parallel to PS.

RY = 9 cm, QR = a cm and YS = b cm

Area of PQRS = 84 cm²

Area of PXYS = 21 cm²

To find:

The value of a and b.

Solution:

RS = 9 + b

Area of rectangle = length × width

Area of PQRS = QR × RY

QR × RS = 84

----------- (1)

Area of PXYS = XY × PS

XY × PS = 21

(since QR = XY)

----------- (2)

Substitute (2) in (1).

Subtract 21 from both sides, we get

Divide by 9 on both sides, we get

a = 7

Substitute a = 7 in (2).

Divide by 7 on both sides, we get

b = 3

The value of a is 7 cm and b is 3 cm.

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh