You pick a card at random, put it back, and then pick another card at random.
5 6 7 8
What is the probability of picking a 7 and then picking a number less than 7?
Write your answer as a percentage.

75%

Step-by-step explanation: The total number of numbers then take the numbers that were seven or less than seven put that into a fraction and then divide it and put it in a percent.

The answer for the first question I believe is 1/4 or 25%. The second answer is 2/4, 1/2 which is 50%

Step-by-step explanation:

There are only 4 options to pick from, and 7 is only one option, thus being 1/4 the possibilities. 1/4 as a percentage is 25% multiply 1/4 by 25 to get a denominator of 100, and a numerator of 25, 25 being the percentage. 5, and 6 are the only numbers less than 7. that means there are 2 choices out of 4 that are less that 7. The fraction form would be 2/4, or 1/2 simplified. and then multiply the numerator and denominator by 50 to get an answer of 50/100 or 50%

a4 - 3a2 - 1

step-by-step explanation:

step   1   :

equation at the end of step   1   :

  ((a4) -   3a2) -   1

step   2   :

trying to factor by splitting the middle term

2.1     factoring   a4-3a2-1  

the first term is,   a4   its coefficient is   1 .

the middle term is,   -3a2   its coefficient is   -3 .

the last term, "the constant", is   -1  

its c or d   take a lucky guess my dude