The projectile motion of an object can be modeled using s(t)=gt^2+v0t+s0, where g is the acceleration due to gravity, t is the time in seconds since launch ,s(t) is the height after t seconds, v0 is the initial velocity, and s0 is the initial height. The acceleration due to gravity is -4.9m/s^2. A rocket is launched from the ground at an initial velocity of 39.2 meters per second. Which equation can be used to model the height of the rocket after t seconds?

S(t) = -4.9t^2 + Vot + 282.24

Step-by-step explanation:

Since the rocket is launched from the ground, So = 0 and S(t) = 0

Using s(t)=gt^2+v0t+s0 to get time t

Where g acceleration due to gravity = -4.9m/s^2. and

initial velocity = 39.2 m/a

0 = -4.9t2 + 39.2t

4.9t = 39.2

t = 8s

Substitute t in the model equation

S(t) = -49(8^2) + 3.92(8) + So

Let S(t) =0

0 = - 313.6 + 31.36 + So

So = 282.24m

The equation that can be used to model the height of the rocket after t seconds will be:

S(t) = -4.9t^2 + Vot + 282.24

11

step-by-step explanation:

32.50-7.50=25

225/25=11

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: